客户端脚本验证码总结(涵盖大部分表单验证可以考虑加入精华)

来源: 作者: 2007-11-19 出处:pcdog.com

     function Jtrim(str)  //去空隔函数
{

        var i = 0;
        var len = str.length;
        if ( str == "" ) return( str );
        j = len -1;
        flagbegin = true;
        flagend = true;
        while ( flagbegin == true && i< len)
        {
           if ( str.charAt(i) == " " )
                {
                  i=i+1;
                  flagbegin=true;
                }
                else
                {
                        flagbegin=false;
                }
        }

        while  (flagend== true && j>=0)
        {
            if (str.charAt(j)==" ")
                {
                        j=j-1;
                        flagend=true;
                }
                else
                {
                        flagend=false;
                }
        }

        if ( i > j ) return ("")

        trimstr = str.substring(i,j+1);
        return trimstr;
}

        function isNumber(s) //数字判断函数
        {
                var digits = "0123456789";
                var i = 0;
                var sLength = s.length;

                while ((i < sLength))
                {
                        var c = s.charAt(i);
                        if (digits.indexOf(c) == -1) return false;
                        i++;
                }

                return true;
        }
function isemail (s)//验证E-MAIL格式函数
{
        
        if (s.length > 100)
        {
                window.alert("email地址长度不能超过100位!");
                return false;
        }

         var regu = "^(([0-9a-zA-Z]+)|([0-9a-zA-Z]+[_.0-9a-zA-Z-]*[0-9a-zA-Z]+))@([a-zA-Z0-9-]+[.])+([a-zA-Z]{2}|net|NET|com|COM|gov|GOV|mil|MIL|org|ORG|edu|EDU|int|INT)$"
         var re = new RegExp(regu);
         if (s.search(re) != -1) {
               return true;
         } else {
               window.alert ("请输入有效合法的E-mail地址 !")
               return false;
         }
}
//判断是否中文函数
function ischinese(s){
var ret=true;
for(var i=0;i<s.length;i++)
ret=ret && (s.charCodeAt(i)>=10000);
return ret;
}
//--------------------------------------------------------------------------------
function ismit()//判断radio是否没有选择函数
{
        var count=0;
        for (ii=0;ii<myform.elements.length;ii++)
        {
                if (myform.elements[ii].type=="radio" && myform.elements[ii].checked==true)
                {
                                count++;
                }
        }
          
    &n

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